Java) Stream.of()

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Stream.of

    Stream<int[]> stream = Stream.of(new int[3]);
    Stream<char[]> stream1 = Stream.of(new char[3]);

    public static<T> Stream<T> of(T t) {
        return StreamSupport.stream(new Streams.StreamBuilderImpl<>(t), false);
    }

The Stream.of above leads into StreamSupport.stream.

    Stream<Car> carStream = Stream.of(new Car[3]);
    Stream<String> stringStream = Stream.of(new String[3]);

    @SafeVarargs
    @SuppressWarnings("varargs") // Creating a stream from an array is safe
    public static<T> Stream<T> of(T... values) {
        return Arrays.stream(values);
    }

The Stream.of above leads into Arrays.stream.
... values means the arguments come in as varargs, and it looks like the calling function receives them in a form equivalent to T[] v = values;.

This works through overloading, but does that mean the constructor for a primitive-type array and the constructor for a reference-type array behave differently?

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As it turns out, a primitive type comes in still wrapped as an array, while a reference type comes in with the array stripped away.